**Formulas**

**Approximate 1/4 mile equations:**

**Trap Speed: TS = 235([hp/weight]^[1/3])**

Trap Speed, **TS**, equals 235 times the quantity:
horsepower, **hp**, divided by **weight** of your vehicle, quantity:
raised to the 1/3 power (cubed root).

**1/4 mile time: ET = 5.5([weight/hp])^[1/3])**

1/4 mile elapsed time, **ET**, is equal to 5.5 times the
quantity: **weight** of your vehicle divided by horsepower,** hp**,
quantity raised to the** **1/3 power (cubed root). Please note, in my
Data Tables section I use this equation for a dada
table but I used** **6.357 instead of the 5.5 as the weighted constant
because I felt it reflects a more conservative scale for weight loss and 1/4
mile times.

**Horsepower from time: hp = 200weight/(ET^3) **

Horsepower, **hp**, is equal to 200 times weight of your
vehicle divided by your 1/4 mile elapsed time, **ET**, to the third power.

**Horsepower from Trap Speed: hp = weight ([TS/234]^3)**

Horsepower, **hp**, is equal to the weight of your vehicle
times the quantity: Trap Speed, **TS**, divided by 234, quantity raised to
the third power.

**Dynamic equations (equations that do not involve mass):**

**hp = vam**

Horsepower, **hp**, equals velocity, **v**, times
acceleration,** a**, times mass, **m**.

**hp = (rpm*torque)/5252 **

Horsepower,** hp**, equals engine **rpm**, times **torque**
divided by 5252 (that's why horsepower and torque always equal at 5252).

**Kinematic equations (equations that do not involve mass):**

**d = vt **

**d**, distance equals a constant velocity, **v**, times
time, **t**. This equation does not really show us anything neat about
our vehicles, but it is the definition of velocity, which gives us our next
equation.

**d = 0.5at^2**

**d**, distance equals 0.5 times acceleration, **a**,
times time, **t**, squared. We can adapt this to measure acceleration
in **G**s. One G is 32.1 fps^2.

**d = 16.05at^2**

Distance,** d**, is in feet, **a** is acceleration in Gs
and **t** is time in seconds. A stock sports car can accelerate off the
line at about 0.5 Gs. In 10 seconds that sports car can travel 802.5 feet
(d = 16.05*0.5G*10s^2). We can then manipulate this formula to give us
acceleration in Gs if we know the amount of time it takes to travel a fixed
distance: **a = d / (16.05t^2)**

**s = (rpm*td) / (wr*gr*336.13524)**

Your speed in MPH, **s**, is equal to the quantity: engine **
rpm** times tire diameter, **td**, in inches, divided by the quantity:
wheel ratio (rear end ratio or axle ratio), **wr**, times the transmission
gear ratio,** gr**, you are in, times 336.1354 (to convert inches to miles
and minutes to hours).

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